Physics

Kinetic Energy Calculator

Calculate kinetic energy using KE = ½mv². Enter mass and velocity to find energy in joules, kJ, or kWh. Includes speed doubling examples and crash physics.

Free No sign-up Instant results

Kinetic energy is the energy an object possesses due to its motion. The faster an object moves, or the heavier it is, the more kinetic energy it carries — and the more energy is required to stop it.

Kinetic Energy Formula

KE = ½ × m × v²

Where:

  • KE = Kinetic energy in joules (J)
  • m = Mass in kilograms (kg)
  • v = Velocity in metres per second (m/s)

Example: A 1,000 kg car travelling at 14 m/s (50 km/h / 31 mph):

KE = 0.5 × 1,000 × 14² = 0.5 × 1,000 × 196 = 98,000 J = 98 kJ

Why Velocity Matters More Than Mass

The quadratic relationship between speed and kinetic energy is one of the most important concepts in crash physics — and everyday driving.

Because kinetic energy uses v², doubling speed quadruples kinetic energy:

SpeedKE (1,000 kg car)Relative to 30 mph
30 mph (13.4 m/s)89.8 kJ
60 mph (26.8 m/s)359 kJ
90 mph (40.2 m/s)808 kJ
120 mph (53.6 m/s)1,436 kJ16×

A car at 60 mph doesn't just need twice the braking distance of a car at 30 mph — it needs four times the distance. This is the physics behind speed limit enforcement near schools and pedestrian zones.

Kinetic Energy in Real Scenarios

ObjectMassSpeedKinetic Energy
Tennis ball (serve)0.058 kg70 m/s (252 km/h)142 J
70 kg cyclist90 kg total8 m/s (29 km/h)2,880 J
1,000 kg car1,000 kg14 m/s (50 km/h)98,000 J (98 kJ)
40-tonne lorry40,000 kg25 m/s (90 km/h)12,500,000 J (12.5 MJ)
Boeing 747 landing300,000 kg70 m/s (252 km/h)735,000,000 J (735 MJ)
Meteorite (small)1,000 kg20,000 m/s200,000,000,000 J (200 GJ)

Energy Unit Conversions

UnitEquivalentWhen used
1 joule (J)1 kg·m²/s²Physics calculations
1 kilojoule (kJ)1,000 JCars, machinery
1 megajoule (MJ)1,000,000 JLarge vehicles, explosions
1 kilowatt-hour (kWh)3,600,000 JElectricity billing
1 calorie (cal)4.184 JChemistry (not nutrition)
1 kilocalorie (kcal)4,184 JFood/nutrition labelling
1 BTU1,055 JUS heating/cooling

Example: A 1,500 kg car at 100 km/h has KE = 0.5 × 1,500 × 27.78² = 578,750 J ≈ 579 kJ ≈ 0.161 kWh.

That's the same energy as running a 160W light bulb for one hour — consumed entirely in the braking process.

The Work-Energy Theorem

Kinetic energy and the work done by forces are directly related:

Work done (J) = Change in kinetic energy (J)
W = KE_final − KE_initial

Braking example: A 1,200 kg car brakes from 60 mph (26.8 m/s) to 0:

KE_initial = 0.5 × 1,200 × 26.8² = 430,752 J
KE_final = 0
Work done by brakes = −430,752 J

The brakes must absorb 430 kJ — this energy becomes heat in the brake discs and pads.

Kinetic Energy vs Potential Energy

Kinetic energy (motion) and potential energy (position/height) convert into each other in conservative systems:

Potential energy: PE = m × g × h
(where h = height in metres, g = 9.81 m/s²)

A 70 kg person at the top of a 10-metre diving board:

PE = 70 × 9.81 × 10 = 6,867 J

At the water surface (h = 0), all potential energy has converted to kinetic energy:

KE = 6,867 J → v = √(2 × KE ÷ m) = √(2 × 6,867 ÷ 70) = 14 m/s (50.4 km/h)

Frequently Asked Questions

What happens to kinetic energy when an object stops?

Kinetic energy is converted into other forms. In braking: heat in brake pads and discs. In a collision: deformation energy (crumpling metal), sound, and heat. In friction: heat. Energy is never destroyed — it changes form, per conservation of energy.

Does kinetic energy depend on direction?

No. Kinetic energy is a scalar quantity — it has magnitude but no direction. A car moving north at 60 mph and a car moving east at 60 mph have the same kinetic energy, even though their velocities (vector quantities) are different.

Why is there a ½ in the kinetic energy formula?

The ½ comes from the calculus derivation. Force = ma, and kinetic energy is the work done accelerating from rest: KE = ∫F·dx. Substituting F = ma and using the kinematic relationship v² = 2as gives KE = ½mv². The ½ is exact, not an approximation.

What is rotational kinetic energy?

Objects can also have rotational kinetic energy from spinning: KE_rot = ½ × I × ω², where I is the moment of inertia (kg·m²) and ω is angular velocity (rad/s). A spinning flywheel or a rolling tyre has both translational and rotational kinetic energy.

How does aerodynamic drag relate to kinetic energy?

Aerodynamic drag increases with the square of speed (F_drag ∝ v²). Combined with kinetic energy also increasing as v², fuel consumption from drag increases as v³ — which is why driving at 80 mph uses dramatically more fuel than 60 mph. Reducing speed from 80 to 70 mph cuts drag-related fuel consumption by about 30%.

Related Calculators